0,0625t^2-2t-10=0

Solution for 0,0625t^2-2t-10=0 equation:

0.0625t^2-2t-10=0

a = 0.0625; b = -2; c = -10;
Δ = b2-4ac
Δ = -22-4·0.0625·(-10)
Δ = 6.5
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{6.5}}{2*0.0625}=\frac{2-\sqrt{6.5}}{0.125}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{6.5}}{2*0.0625}=\frac{2+\sqrt{6.5}}{0.125}
$